Statistics MCQs for UPSC Prelims

162 practice questions covering Statistics, organised into 2 topics. 162 questions include a written explanation. Pick a topic below, or try the samples first.

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Sample questions

Q1
medium
For a set of eight observations, $\sum x_i = 40$ and $\sum x_i^2 = 272$. Find the standard deviation.
  1. A $5.83$
  2. B $9$
  3. C $34$
  4. D $3$
Show answer and explanation

Correct answer: D - $3$

The mean is $\frac{40}{8} = 5$, so the variance is $\frac{272}{8} - 5^2 = 34 - 25 = 9$ and the standard deviation is $3$. The value $9$ is the variance itself. The value $34$ is $\frac{\sum x_i^2}{n}$ with the $\bar{x}^2$ term forgotten, and $5.83$ is $\sqrt{34}$, the same slip carried into the square root.
Q2
medium
Consider these two statements. I: For any data set, the mean deviation about the median is never greater than the mean deviation about the mean. II: The mean deviation about the median is negative when most of the observations lie below the median. Which is correct?
  1. A Only I is true
  2. B Only II is true
  3. C Both I and II are true
  4. D Neither I nor II is true
Show answer and explanation

Correct answer: A - Only I is true

The sum of absolute deviations is smallest when measured about the median, so the mean deviation about the median cannot exceed the one about the mean, making I true. II is false because absolute deviations are distances and can never be negative, whatever the shape of the data. So the options accepting II fail, and I cannot be rejected.
Q3
easy
Find the mean deviation about the mean of the five observations $4, 7, 8, 9, 12$.
  1. A $2$
  2. B $8$
  3. C $10$
  4. D $0$
Show answer and explanation

Correct answer: A - $2$

The mean is $\frac{40}{5} = 8$. The absolute deviations are $4, 1, 0, 1, 4$, whose sum is $10$, so the mean deviation is $\frac{10}{5} = 2$. The value $0$ comes from adding the deviations with their signs, which always cancel to zero. The value $10$ is the sum of the absolute deviations before dividing, and $8$ is the mean itself.
Q4
easy
In the mode formula $\text{Mode} = l + \left(\frac{f_1-f_0}{2f_1-f_0-f_2}\right)h$ for grouped data, what does $f_1$ stand for?
  1. A The size of each class
  2. B The total of all the frequencies
  3. C The frequency of the class just before the modal class
  4. D The frequency of the modal class
Show answer and explanation

Correct answer: D - The frequency of the modal class

In the formula $f_1$ is the frequency of the modal class itself, while $f_0$ and $f_2$ are the frequencies of the classes just before and just after it. The total frequency is written $\sum f_i$ and appears in the mean and median formulas, not here. The class size is $h$, the letter multiplying the bracket.
Q5
medium
Assertion (A): For the distribution $0-10$ ($3$), $10-20$ ($9$), $20-30$ ($7$), $30-40$ ($1$), the mode lies between $10$ and $20$. Reason (R): The mode of a grouped distribution is always equal to the class mark of the modal class.
  1. A Both A and R are true, and R is the correct explanation of A
  2. B Both A and R are true, but R is not the correct explanation of A
  3. C A is true, but R is false
  4. D A is false, but R is true
Show answer and explanation

Correct answer: C - A is true, but R is false

The greatest frequency is $9$, so the modal class is $10-20$ and the mode does lie between $10$ and $20$, making A true. R is false: the formula gives $10 + \frac{6}{18-3-7}\times 10 = 17.5$ here, not the class mark $15$, and in general the mode need not sit at the middle of the modal class.
Q6
medium
A factory tells a buyer that its mean daily output is $500$ units. The buyer also asks for the standard deviation of the daily output. What is the buyer trying to find out?
  1. A How steady the daily output is from day to day
  2. B Whether the reported mean has been computed correctly
  3. C The total output of the factory for the month
  4. D The most frequently occurring daily output
Show answer and explanation

Correct answer: A - How steady the daily output is from day to day

The standard deviation measures how far the daily figures typically lie from their average, so a small value means a dependable, steady supply. The total needs only the mean and the number of days, not the spread. The standard deviation cannot check whether a mean was computed correctly. The most frequent value is the mode, which is a different measure altogether.

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