Q1
hard
Three numbers standing next to each other in the Virahanka sequence add up to $68$. What is the largest of the three?
- A $55$
- B $13$
- C $21$
- D $34$
Show answer and explanation
Correct answer: D - $34$
If the first two are $a$ and $b$, the third is $a + b$, so the total is $2(a + b) = 68$ and $a + b = 34$. The largest of the three is that third number, $34$, and the triple is $13$, $21$, $34$. The values $21$ and $13$ are the two smaller members, and $55$ is the number that follows the triple.