26 practice questions on the-distributive-property from the We Distribute, Yet Things Multiply section of the UPSC Prelims syllabus.
26 come with a written explanation.
Try the sample set below - the answer stays hidden until you ask for it.
8 Easy13 Medium5 Hard
Sample questions
Q1
medium
What is the quickest correct mental method for $7 \times 99$?
A$7 \times 100 - 1 = 699$
B$7 \times 90 + 9 = 639$
C$7 \times 100 - 7 = 693$
D$7 \times 100 + 7 = 707$
Show answer and explanation
Correct answer: C - $7 \times 100 - 7 = 693$
Since $99 = 100 - 1$, the product is $700 - 7 \times 1 = 693$. Subtracting only $1$ forgets to multiply the correction, the third option leaves the $9$ unmultiplied, and the last adds where it should subtract.
Q2
medium
Which single product equals $9 \times 25 + 9 \times 15$?
A$9 + 40$
B$9 \times 40$
C$18 \times 40$
D$9 \times 375$
Show answer and explanation
Correct answer: B - $9 \times 40$
The common factor $9$ can be taken out, leaving $9 \times (25 + 15) = 9 \times 40 = 360$. Multiplying $25$ by $15$ is wrong because the two products are added, not multiplied, doubling the $9$ counts the factor twice, and the last option drops the multiplication.
Q3
hard
A trader sells $98$ packets of tea at ₹$45$ each. Which calculation gives the correct total?
Writing $98$ as $100 - 2$ gives $4500 - 90 = 4410$, and $45 \times 98$ is indeed ₹$4410$. The second subtracts $2$ rather than $2$ lots of ₹$45$, the third adds the correction instead of subtracting it, and the fourth splits $98$ as $90 + 2$, which is only $92$.
Q4
easy
Which of these writes $4 \times 37$ as a sum of two products?
A$4 + 30 \times 7$
B$4 \times 30 + 4 \times 7$
C$4 \times 30 + 7$
D$4 \times 3 + 4 \times 7$
Show answer and explanation
Correct answer: B - $4 \times 30 + 4 \times 7$
Splitting $37$ into $30 + 7$ and multiplying each part by $4$ gives $120 + 28 = 148$, which is $4 \times 37$. The second leaves the $7$ unmultiplied, the third changes the operations, and the fourth uses $3$ in place of $30$.
Q5
medium
Assertion (A): $7 \times 14$ can be worked out as $7 \times 10 + 7 \times 4$. Reason (R): A rectangle $7$ units by $14$ units can be cut into a $7$ by $10$ rectangle and a $7$ by $4$ rectangle, and the two areas add up to the whole.
ABoth A and R are true, and R is the correct explanation of A
BBoth A and R are true, but R is not the correct explanation of A
CA is true, but R is false
DA is false, but R is true
Show answer and explanation
Correct answer: A - Both A and R are true, and R is the correct explanation of A
Both sides of A equal $98$, and the cut described in R really does split the rectangle into those two pieces with no overlap and nothing left out. The picture is exactly why the split of the product works, so R explains A.
Q6
easy
Two claims are made about $7 \times (50 - 1)$. (I) It equals $7 \times 50 - 7 \times 1$. (II) It equals $7 \times 50 - 1$. Which is correct?
ANeither (I) nor (II)
BOnly (I)
CBoth (I) and (II)
DOnly (II)
Show answer and explanation
Correct answer: B - Only (I)
The product is $7 \times 49 = 343$. Claim (I) gives $350 - 7 = 343$, so it holds. Claim (II) leaves the $1$ unmultiplied and gives $349$, so it fails. Exactly one of the two is right.
Q7
easy
Which expression is equal to $8 \times (10 - 2)$?
A$8 \times 10 - 2$
B$8 \times 10 - 8 \times 2$
C$8 - 10 \times 2$
D$8 \times 10 + 8 \times 2$
Show answer and explanation
Correct answer: B - $8 \times 10 - 8 \times 2$
The outside factor multiplies both terms and the minus sign is kept, giving $80 - 16 = 64$, which is $8 \times 8$. The second option forgets to multiply the $2$, the third changes the sign, and the fourth rearranges the numbers entirely.
Q8
hard
Ramesh buys $14$ notebooks costing ₹$23$ each and $14$ pens costing ₹$17$ each. Which single multiplication gives his total bill?
A$14 \times 23 \times 17$
B$14 \times 40$
C$14 + 40$
D$28 \times 40$
Show answer and explanation
Correct answer: B - $14 \times 40$
The bill is $14 \times 23 + 14 \times 17$, and taking out the common $14$ leaves $14 \times (23 + 17) = 14 \times 40 = 560$. Multiplying the two prices has no meaning here, doubling the $14$ counts every item twice, and the last option abandons multiplication altogether.
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