29 practice questions on patterns-in-numbers from the Patterns in Mathematics section of the UPSC Prelims syllabus.
29 come with a written explanation.
Try the sample set below - the answer stays hidden until you ask for it.
9 Easy14 Medium6 Hard
Sample questions
Q1
medium
A sequence begins $6, 11, 16, 21, \ldots$. Which term of this sequence is $56$?
AThe $12$th term
BThe $9$th term
CThe $11$th term
DThe $10$th term
Show answer and explanation
Correct answer: C - The $11$th term
The sequence starts at $6$ and rises by $5$ each time, so the $n$th term is $5n + 1$. Setting $5n + 1 = 56$ gives $n = 11$. The $10$th term is $51$ and the $12$th is $61$, so neither is $56$, and the $9$th term is only $46$.
Q2
easy
Which sequence lists the counting numbers?
A$0, 2, 4, 6, 8, \ldots$
B$1, 1, 1, 1, 1, \ldots$
C$1, 3, 5, 7, 9, \ldots$
D$1, 2, 3, 4, 5, \ldots$
Show answer and explanation
Correct answer: D - $1, 2, 3, 4, 5, \ldots$
The counting numbers begin at $1$ and increase by $1$ each time, giving $1, 2, 3, 4, 5, \ldots$. The second sequence lists even numbers including $0$, the third lists odd numbers, and the fourth is the constant sequence of $1$s.
Q3
easy
Which sequence is obtained by skip-counting in steps of $4$ starting from $4$?
A$4, 8, 12, 16, 20, \ldots$
B$1, 4, 9, 16, 25, \ldots$
C$4, 16, 64, 256, \ldots$
D$4, 6, 8, 10, 12, \ldots$
Show answer and explanation
Correct answer: A - $4, 8, 12, 16, 20, \ldots$
Skip-counting by $4$ adds $4$ each time, giving the multiples of $4$: $4, 8, 12, 16, 20, \ldots$. The second sequence steps by $2$, the third lists square numbers, and the fourth multiplies by $4$ each time rather than adding.
Q4
medium
What are the next two terms of $100, 91, 82, 73, \ldots$?
A$64$ and $54$
B$64$ and $55$
C$63$ and $54$
D$65$ and $56$
Show answer and explanation
Correct answer: B - $64$ and $55$
Each term decreases by $9$, so the next two are $73 - 9 = 64$ and $64 - 9 = 55$. The other options apply a step of $10$ or mix steps, breaking the constant difference of $9$.
Q5
easy
What is the rule of the sequence $5, 10, 15, 20, 25, \ldots$?
AAdd the two previous terms
BAdd $5$ to the previous term
CAdd $10$ to the previous term
DMultiply the previous term by $2$
Show answer and explanation
Correct answer: B - Add $5$ to the previous term
Each term exceeds the one before by $5$, so the rule is to add $5$. Doubling would give $5, 10, 20, 40$, adding the two previous terms would give $5, 10, 15, 25$, and adding $10$ would give $5, 15, 25$, none of which matches.
Q6
medium
Chairs are placed in a hall so that row $1$ has $1$ chair, row $2$ has $2$ chairs, row $3$ has $3$ chairs, and so on. How many chairs are in row $9$?
A$10$
B$18$
C$45$
D$9$
Show answer and explanation
Correct answer: D - $9$
The chairs follow the counting numbers, so row $9$ holds $9$ chairs. Answering $10$ shifts the row number by one, $45$ gives the total chairs in the first nine rows rather than that row alone, and $18$ doubles the row number.
Q7
medium
A frog starts at $0$ and jumps forward $7$ units each time. Which of these numbers will it land on?
A$50$
B$56$
C$60$
D$45$
Show answer and explanation
Correct answer: B - $56$
The frog lands only on multiples of $7$, and $56 = 7 \times 8$. The numbers $50$, $60$ and $45$ leave remainders $1$, $4$ and $3$ when divided by $7$, so the frog jumps over each of them.
Q8
easy
What is the next term in the sequence $1, 2, 4, 8, 16, \ldots$?
A$32$
B$18$
C$20$
D$24$
Show answer and explanation
Correct answer: A - $32$
Each term is double the one before, so after $16$ comes $16 \times 2 = 32$. Answering $24$ adds $8$, $20$ adds $4$, and $18$ adds $2$, all treating a doubling pattern as if it were addition.
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