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Quadrilateral and Parallelogram

**Correct Marks**
2

**Incorrectly Marks**
-0.5

Q 1. The points A (-2, -1), B (1, 0), C (4, 3) and D (1, 2) are corners of a

Square

Trapezium

Parallelogram

Rectangle

{tex} AB = \sqrt{3^{2}+1^{2}}=\sqrt{10} {/tex}

{tex} BC = \sqrt{3^{2}+3^{2}}=3\sqrt{2} {/tex}

{tex} CD = \sqrt{3^{2}+1^{2}}=\sqrt{10} {/tex}

{tex} DA = \sqrt{3^{2}+3^{2}}=3\sqrt{2} {/tex}

Therefore, Diagonal AC = {tex} \sqrt{6^{2}+4^{2}}=\sqrt{52} {/tex}

and diagonal BD = {tex} \sqrt{0+2^{2}}=2 {/tex}

Since opposite sides are equal and the diagonals are not equal, hence ABCD is a parallelogram.

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