Correct Marks 2
Incorrectly Marks -0.5
Q 1. The points A (-2, -1), B (1, 0), C (4, 3) and D (1, 2) are corners of a
Square
Trapezium
Parallelogram
Rectangle
{tex} AB = \sqrt{3^{2}+1^{2}}=\sqrt{10} {/tex}
{tex} BC = \sqrt{3^{2}+3^{2}}=3\sqrt{2} {/tex}
{tex} CD = \sqrt{3^{2}+1^{2}}=\sqrt{10} {/tex}
{tex} DA = \sqrt{3^{2}+3^{2}}=3\sqrt{2} {/tex}
Therefore, Diagonal AC = {tex} \sqrt{6^{2}+4^{2}}=\sqrt{52} {/tex}
and diagonal BD = {tex} \sqrt{0+2^{2}}=2 {/tex}
Since opposite sides are equal and the diagonals are not equal, hence ABCD is a parallelogram.