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JEE Advanced > Solutions

Explore popular questions from Solutions for JEE Advanced. This collection covers Solutions previous year JEE Advanced questions hand picked by experienced teachers.

Q 1.

Correct4

Incorrect-1

An azeotropic solution of two liquids has boiling point lower than either of them when it

A

shows negative deviation from Raoult's law

B

shows no deviation from Raoult's law

shows positive deviation from Raoult's law

D

is saturated

Explanation

Q 2.

Correct4

Incorrect-1

For a dilute solution, Raoult's law states that :

A

the lowering of vapour pressure is equal to the mole fraction of solute.

the relative lowering of vapour pressure is equal to the mole fraction of solute.

C

the relative lowering of vapour pressure is proportional to the amount of solute in solution.

D

the vapour pressure of the solution is equal to the mole fraction of solvent.

Explanation

Q 3.

Correct4

Incorrect-1

When mercuric iodide is added to the aqueous solution of potassium iodide then

freezing point is raised.

B

freezing point is lowered.

C

freezing point does not change.

D

boiling point does not change.

Explanation

Q 4.

Correct4

Incorrect-1

Which of the following {tex} 0.1\ \mathrm { M } {/tex} aqueous solutions will have the lowest freezing point?

Potassium sulphate

B

Sodium chloride

C

Urea

D

Glucose

Explanation

Q 5.

Correct4

Incorrect-1

The freezing point of equimolal aqueous solutions will be highest for:

A

{tex} \mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { NH } _ { 3 } \mathrm { Cl } {/tex} (aniline hydrochloride)

B

{tex} \mathrm { Ca } \left( \mathrm { NO } _ { 3 } \right) _ { 2 } {/tex}

C

{tex} \mathrm { La } \left( \mathrm { NO } _ { 3 } \right) _ { 3 } {/tex}

{tex} \mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 } ( \text { glucose } ) {/tex}

Explanation

Q 6.

Correct4

Incorrect-1

{tex}0.2{/tex} molal acid {tex} \mathrm { HX } {/tex} is {tex} 20 \% {/tex} ionised in solution. {tex} \mathrm { K } _ { f } = 1.86 \mathrm { K } {/tex} molality {tex} ^ { - 1 } . {/tex} The freezing point of the solution is :

{tex} - 0.45 {/tex}

B

{tex} - 0.90 {/tex}

C

{tex} - 0.31 {/tex}

D

{tex} - 0.53 {/tex}

Explanation

Q 7.

Correct4

Incorrect-1

The molecular weight of benzoic acid in benzene as determined by depression in freezing point method corresponds to :

A

ionization of benzoic acid.

dimerization of benzoic acid.

C

trimerization of benzoic acid.

D

solvation of benzoic acid.

Explanation

Q 8.

Correct4

Incorrect-1

During depression of freezing point in a solution the following are in equililbrium

liquid solvent, solid solvent

B

liquid solvent, solid solute

C

liquid solute, solid solute

D

liquid solute, solid solvent

Explanation

Q 9.

Correct4

Incorrect-1

The elevation in boiling point of a solution of {tex} 13.44 \mathrm { g } {/tex} of {tex} \mathrm { CuCl } _ { 2 } {/tex} in {tex} 1 \mathrm { kg } {/tex} of water using the following information will be (Molecular weight of {tex} \mathrm { CuCl } _ { 2 } = 134.4 {/tex} and {tex} \mathrm { K } _ { b } = 0.52 \mathrm { K } {/tex} molal {tex} ^ { - 1 } {/tex} )

0.16

B

0.05

C

0.1

D

0.2

Explanation

Q 10.

Correct4

Incorrect-1

When {tex} 20 \mathrm { g } {/tex} of naphthoic acid {tex} \left( \mathrm { C } _ { 11 } \mathrm { H } _ { 8 } \mathrm { O } _ { 2 } \right) {/tex} is dissolved in {tex}50 \mathrm { g } {/tex} of benzene {tex} \left( \mathrm { K } _ { f } = 1.72\ \mathrm { K }\ \mathrm { kg }\ \mathrm { mol } ^ { - 1 } \right) , {/tex} a freezing point depression of {tex} 2 \mathrm { K } {/tex} is observed. The Van't Hoff factor (i) is

0.5

B

1

C

2

D

3

Explanation

Q 11.

Correct4

Incorrect-1

The Henry's law constant for the solubility of {tex} \mathrm { N } _ { 2 } {/tex} gas in water at {tex} 298 \mathrm { K } {/tex} is {tex} 1.0 \times 10 ^ { 5 } \mathrm { atm } {/tex}. The mole fraction of {tex} \mathrm { N } _ { 2 } {/tex} in air is {tex} 0.8 . {/tex} The number of moles of {tex} \mathrm { N } _ { 2 } {/tex} from air dissolved in 10 moles of water at {tex} 298 \mathrm { K } {/tex} and {tex}5{/tex} atm pressure is

{tex} 4.0 \times 10 ^ { - 4 } {/tex}

B

{tex} 4.0 \times 10 ^ { - 5 } {/tex}

C

{tex} 5.0 \times 10 ^ { - 4 } {/tex}

D

{tex} 4.0 \times 10 ^ { - 6 } {/tex}

Explanation

Q 12.

Correct4

Incorrect-1

Dissolving {tex} 120 \mathrm { g } {/tex} of urea (mol. wt. 60 ) in {tex} 1000 \mathrm { g } {/tex} of water gave a solution of density {tex} 1.15 \mathrm { g } / \mathrm { mL } {/tex}. The molarity of the solution is

A

{tex} 1.78\ \mathrm { M } {/tex}

B

{tex} 2.00\ \mathrm { M } {/tex}

{tex} 2.05\ \mathrm { M } {/tex}

D

{tex} 2.22\ \mathrm { M } {/tex}

Explanation

Q 13.

Correct4

Incorrect-1

The freezing point (in {tex}^\circ{/tex}C) of a solution containing {tex} 0.1 \mathrm { g } {/tex} of {tex} \mathrm { K } _ { 3 } \left[ \mathrm { Fe } ( \mathrm { CN } ) _ { 6 } \right] ( \mathrm { Mol } . \text { wt. } 329 ) {/tex} in {tex} 100 \mathrm { g } {/tex} of water {tex} \left( K _ { f } = 1.86\ \mathrm { K } \right. {/tex} {tex} \left. \mathrm { kg }\ \mathrm { mol } ^ { - 1 } \right) {/tex} is

{tex} - 2.3 \times 10 ^ { - 2 } {/tex}

B

{tex} - 5.7 \times 10 ^ { - 2 } {/tex}

C

{tex} - 5.7 \times 10 ^ { - 3 } {/tex}

D

{tex} - 1.2 \times 10 ^ { - 2 } {/tex}

Explanation

Q 14.

Correct4

Incorrect-1

For a dilute solution containing {tex} 2.5 \mathrm { g } {/tex} of a non-volatile non- electrolyte solute in {tex} 100 \mathrm { g } {/tex} of water, the elevation in boiling point at {tex} 1 \mathrm { atm } {/tex} pressure is {tex} 2 ^ { \circ } \mathrm { C } {/tex}. Assuming concentration of solute is much lower than the concentration of solvent, the vapour pressure (mm of Hg) of the solution is (take {tex} \left. K _ { b } = 0.76\ \mathrm { K }\ \mathrm { kg }\ \mathrm { mol } ^ { - 1 } \right) {/tex}

724

B

740

C

736

D

718

Explanation



Q 15.

Correct4

Incorrect-1

Pure water freezes at {tex} 273 \mathrm { K } {/tex} and 1 bar. The addition of {tex} 34.5 \mathrm { g } {/tex} of ethanol to {tex} 500 \mathrm { g } {/tex} of water changes the freezing point of the solution. Use the freezing point depression constant of water as {tex} 2 \ \mathrm { K }\ \mathrm { kg }\ \mathrm { mol } ^ { - 1 } {/tex}. The figures shown below represent plots of vapour pressure (V.P.) versus temperature (T). [ molecular weight of ethanol is {tex} \left. 46\ \mathrm { g }\ \mathrm { mol } ^ { - 1 } \right] {/tex} Among the following, the option representing change in the freezing point is

A

B

D

Explanation

Q 16.

Correct4

Incorrect-1

A molal solution is one that contains one mole of a solute in

{tex} 1000 \mathrm { g } {/tex} of the solvent

B

one litre of the solvent

C

one litre of the solution

D

22.4 litres of the solution

Explanation

Q 17.

Correct4

Incorrect-1

The freezing point of equimolal aqueous solutions will be highest for

A

{tex} \mathrm { C } _ { 6 } \mathrm { H } _ { 5 } \mathrm { NH } _ { 3 } \mathrm { Cl } {/tex} (anilinium chloride)

B

{tex} \mathrm { Ca } \left( \mathrm { NO } _ { 3 } \right) _ { 2 } {/tex}

C

{tex} \mathrm { La } \left( \mathrm { NO } _ { 3 } \right) _ { 3 } {/tex}

{tex} \mathrm { C } _ { 6 } \mathrm { H } _ { 12 } \mathrm { O } _ { 6 } ( \mathrm { glucose } ) {/tex}

Explanation

Q 18.

Correct4

Incorrect-1

A {tex} 0.004 \mathrm { M } {/tex} solution of {tex} \mathrm { K } _ { 2 } \mathrm { SO } _ { 4 } {/tex} is isotonic with a {tex} 0.010 \mathrm { M } {/tex} solution of glucose at the same temperature. The apparent per cent degree of dissociation of {tex} \mathrm { K } _ { 2 } \mathrm { SO } _ { 4 } {/tex} is

A

{tex} 25 \% {/tex}

B

{tex} 50 \% {/tex}

{tex} 75 \% {/tex}

D

{tex} 100 \% {/tex}

Explanation

Q 19.

Correct4

Incorrect-1

When {tex} 20 \mathrm { g } {/tex} of naphthoic acid {tex}( \mathrm { C } _ { 11 } \mathrm { H } _ { 8 } \mathrm { O } _ { 2 } ) {/tex} is dissolved in {tex} 50 \mathrm { g } {/tex} of benzene {tex} ( K _ { \mathrm { f } } = 1.72 \mathrm { K } \mathrm { kg } \mathrm { mol } ^ { - 1 } ) , {/tex} a freezing point depression of {tex} 2 \mathrm { K } {/tex} is observed. The van't Hoff factor (i) is

{tex} 0.5 {/tex}

B

{tex} 1 {/tex}

C

{tex}2 {/tex}

D

{tex} 3 {/tex}

Explanation

Q 20.

Correct4

Incorrect-1

Dissolving {tex} 120 \mathrm { g } \text { of urea (relative molar mass } 60 ) {/tex} in {tex} 1000 \mathrm { g } {/tex} of water gave a solution of density {tex} 1.15 \mathrm { g } {/tex} {tex} \mathrm { mL } ^ { - 1 } . {/tex} The molarity of the solution is

A

{tex} 1.78 \mathrm { M } {/tex}

B

{tex} 2.00 \mathrm { M } {/tex}

{tex} 2.05 \mathrm { M } {/tex}

D

{tex} 2.22 \mathrm { M } {/tex}

Explanation