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JEE Advanced

Explore popular questions from Electrochemistry for JEE Advanced. This collection covers Electrochemistry previous year JEE Advanced questions hand picked by experienced teachers.

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Q 1. The potential of the following cell at {tex} 25 ^ { \circ } \mathrm { C } {/tex} is

A

{tex} - 0.059 \mathrm V {/tex}

B

{tex} 0.050 \mathrm { V } {/tex}

{tex} - 0.59 \mathrm { V } {/tex}

D

{tex} 0.5 \mathrm { V } {/tex}

Explanation

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Q 2. {tex} 0.5 \mathrm { F } {/tex} of electricity is passed through {tex} 500 \mathrm { mL } {/tex} of copper sulphate solution. The amount of copper which can be deposited will be

A

{tex} 63.5 \mathrm g {/tex}

B

{tex} 31.75 \mathrm { g } {/tex}

{tex} 15.8 \mathrm g {/tex}

D

Unpredictable

Explanation

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Q 3. The standard EMF of decinormal calomel electrode is {tex} 0.268 \mathrm { V } . {/tex} The EMF is

A

{tex} - 0.298 \mathrm { V } {/tex}

{tex} 0.327 \mathrm { V } {/tex}

C

{tex} - 0.327 \mathrm { V } {/tex}

D

{tex} 0.298 \mathrm { V } {/tex}

Explanation

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Q 4. {tex} \mathrm { Ag } | \mathrm { Ag } ^\oplus ( 1 \mathrm { M } ) | \mathrm { Ag }^ \oplus { \| \mathrm { Ag } } {/tex}
1 L solution 1 L solution 0.5 F electricity in the LHS (anode) and 1 F of electricity in the RHS (cathode) in first passed making them independent electrolytic cells at 298 K.EMF of the cell after electrolysis will be

A

Increased

B

Decreased

No change

D

Time is also required

Explanation

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Q 5. A current strength of {tex} 1.0 \mathrm { A } {/tex} is passed for {tex} 96.5 \mathrm { s } {/tex} through {tex} 100 \mathrm { mL } {/tex} of a solution of {tex} 0.05 \mathrm { M } \mathrm { KCl } {/tex}. The concentration of the final solution with respect to {tex} \mathrm {\stackrel{\ominus} OH } {/tex} ions is

A

{tex} 0.005 \mathrm { M } {/tex}

B

{tex} 0.05 \mathrm { M } {/tex}

{tex} 0.01 \mathrm { M } {/tex}

D

{tex} 0.001 \mathrm { M } {/tex}

Explanation

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Q 6.

The standard reduction potential values of three metallic cations, X, Y, and Z are 0.52, , and V, respectively. The order of reducing power of the corresponding metal is

Y > Z > X

B

X > Y > Z

C

Z >Y > X

D

Z > X > Y

Explanation

The smaller the reduction potential of a substance, the more is its reducing power. (Y > Z > X)

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Q 7.

What is the value of if and for 0.04 M of at ?

A

9.3

9.2

C

4.7

D

4.8

Explanation

Use:

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Q 8.

of KOH solution was titrated with 0.20 M solution in a conductivity cell. The data obtained were plotted to give the graph shown below

The concentration of the KOH solution was

0.30 mol

B

0.15 mol

C

0.12 mol

D

0.075 mol

Explanation

Equivalent point (from graph)

Using of acid of base

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Q 9.

The resistance of 1 N solution of acetic acid 250 ohm, when measured in a cell of cell constant . The equivalent conductance (in ) of 1 N acetic acid is

4.6

B

9.2

C

18.4

D

0.023

Explanation

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Q 10.

The two Pt electrodes fitted in a conductance cell are 1.5 cm apart while the crosssectional area of each electrode is 0.75 cm. What is the cell constant?

A

1.125

B

0.5 cm

C

Explanation

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Q 11.

Given that:

Predict which of the following is true

ions will be able to reduce bromine

B

ions will be able to reduce iodine

C

Iodine will be able to reduce bromine

D

Bromine will be able to reduce iodide ions

Explanation

Since the reduction potential of is greater than the reduction potential of so ions will reduce

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Q 12.

What is the potential of the cell containing two hydrogen electrodes as represented below?

A

V

B

V

0.236 V

D

0.0591 V

Explanation

Or V

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Q 13.

The standard EMF of quinhydrone electrode is 0.699 V. The EMF of the quinhydrone electrode dipped in a solution with pH = 10 is

0.109 V

B

V

C

1.289 V

D

V

Explanation

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Q 14.

The potential of a hydrogen electrode in a solution with at is

A

B

D

0.59

Explanation

V

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Q 15.

Faraday’s laws of electrolysis are related to the

A

The atomic number of the cation

B

The atomic number of anion

The equivalent weight of the electrolyte

D

The speed of the cation

Explanation

Faraday's first law

The amount of substance liberated at the electrode is directly proportional to the quantity of electricity passed

Electrochemical equivalent (ECE) is the amount of substance liberated on passing 1 C of electricity

The ECEs of hydrogen, silver, and copper are 0.00001036, 0.001118, and 0.0003292, respectively

Faraday's second law

If same quantity of electricity (same current for same time) is passed through different electrolytes, the amount of substance liberated at different electrodes is in the ratio of their respective electrochemical equivalent (or equivalent weights)

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Q 16.

500 mL of 1 N solution of was electrolyzed with a current of 2 amperes for 1 hours. What is the normality of the remaining solution?

0.85

B

0.15

C

0.3

D

1

Explanation

Initial of

Electricity passed

of remaining

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Q 17.

A solution of 0.65 A flowing for 10 min deposits 3.0 g of the metal which is monovalent. The atomic mass of the metal is

A

10

50

C

30

D

96.5

Explanation

Let be the atomic weight of metal

1 mol of metal g

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Q 18.

For the electrolytic production of from according to the reaction . How many faradays of electricity would be required to produce 0.5 mole of ?

1

B

2

C

3

D

1.5

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Q 19.

For the half cell

At pH = 2, the electrode potential is

A

1.36 V

B

1.30 V

1.42 V

D

1.20 V

Explanation

In this electrode,

in quihydrone electrode

Hence,

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Q 20.

When electricity is passed through a solution of and 13.5 g of Al is deposited, the number of Faraday must be

A

0.5

B

1

1.5

D

2

Explanation

1 mol of

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Q 21.

Chromium plating can involve the electrolysis of an electrolyte of an acidified mixture of chromic acid and chromium sulphate. If during electrolysis the article being plated increases in mass by 2.6 g and 0.6 of oxygen are evolved at an inert anode, the oxidation state of chromium ions being discharged must be: (assuming atomic weight of Cr = 52 and 1 mole of gas at room temperature and pressure occupies a volume of )

A

B

Zero

1

D

2

Explanation

Oxidation state of

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Q 22.

Given

Which metal will corrode fastest?

A

B

C

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Q 23.

The volume of gases evolved at STP by passing 0.2 A of current for 965 s through an aqueous solution of sodium fumarate is

A

22.4

B

11.2 m

89.6

D

44.8

Explanation

L

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Q 24.

Two platinum electrodes were immersed in a solution of and electric current was passed through the solution. After some time, it was found that colour of disappeared with evolution of gas at the electrode. The colorless solution contains

A

Platinum sulphate

B

Copper hydroxide

C

Copper sulphate

Sulphuric acid

Explanation

At cathode: (reduction)

The blue colour of disappears due to the deposition of Cu on Pt electrode

At anode:

Since oxidation potential oxidation potential of so oxidation of occurs and (g) is evolved at anode

The colourless solution is due to the formation of as follows:

(from anode) +

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Q 25.

Red hot carbon will remove oxygen from the oxides XO and YO but not from ZO. Y will remove oxygen from XO. Use this evidence to deduce the order of activity of the three metals X, Y, and Z, putting the most reactive first

A

X, Y, Z

Z, Y, X

C

Y, X, Z

D

Z, X, Y

Explanation

Carbon is a powerful reducing agent from X and Y but not from Z. Y is more reactive than X

Therefore, reactivity series: