On account of the disruption in education due to the corona pandemic, we're are providing a 7-day Free trial of our platform to teachers. Know More →

JEE Advanced

Explore popular questions from Dual Nature of Matter and Radiation for JEE Advanced. This collection covers Dual Nature of Matter and Radiation previous year JEE Advanced questions hand picked by experienced teachers.

Select Subject

Mathematics

Physics

Chemistry

Dual Nature of Matter and Radiation

Correct Marks 4

Incorrectly Marks -1

Q 1. The kinetic energy of a particle is equal to the energy of a photon. The particle moves at {tex} 5 \% {/tex} of the speed of light. The ratio of the photon wavelength to the de Broglie wavelength of the particle is [No need to use relative formula for the particle {tex} ] {/tex}

40

B

4

C

2

D

80

Explanation

Correct Marks 4

Incorrectly Marks -1

Q 2. Work function of nickel is {tex}5.01 eV{/tex}. When ultraviolet radiation of wavelength {tex} 200 \mathrm { Å } {/tex} is incident on it, electrons are emitted. What will be the maximum velocity of emitted electrons?

A

{tex} 3 \times 10 ^ { 8 } \mathrm { ms } ^ { - 1 } {/tex}

{tex} 6.46 \times 10 ^ { 5 } \mathrm { ms } ^ { - 1 } {/tex}

C

{tex} 10.36 \times 10 ^ { 5 } \mathrm { ms } ^ { - 1 } {/tex}

D

{tex} 8.54 \times 10 ^ { 6 } \mathrm { ms } ^ { - 1 } {/tex}

Explanation

Correct Marks 4

Incorrectly Marks -1

Q 3. The KE of the photoelectrons is {tex} E {/tex} when the incident wavelength is {tex} \lambda / 2 . {/tex} The KE becomes {tex} 2 E {/tex} when the incident wavelength is {tex} \lambda / 3 . {/tex} The work function of the metal is

{tex} h c / \lambda {/tex}

B

{tex} 2 h c / \lambda {/tex}

C

{tex} 3 h c / \lambda {/tex}

D

{tex} h c / 3 \lambda {/tex}

Explanation


Correct Marks 4

Incorrectly Marks -1

Q 4. The energy of a photon is equal to the kinetic energy of a proton. The energy of photon is {tex} E . {/tex} Let {tex} \lambda _ { 1 } {/tex} be the de Broglie wavelength of the proton and {tex} \lambda _ { 2 } {/tex} be the wavelength of the photon. Then, {tex} \lambda _ { 1 } / \lambda _ { 2 } {/tex} is proportional to

A

{tex} E ^ { 0 } {/tex}

{tex} E ^ { 1 / 2 } {/tex}

C

{tex} E ^ { - 1 } {/tex}

D

{tex} E ^ { - 2 } {/tex}

Explanation


Correct Marks 4

Incorrectly Marks -1

Q 5. Find the ratio of de Broglie wavelength of a proton and an {tex} \alpha {/tex} -particle which have been accelerated through same potential difference

{tex} 2 \sqrt { 2 }: 1 {/tex}

B

{tex}3:2{/tex}

C

{tex} 3 \sqrt { 2 }: 1 {/tex}

D

{tex}2:1{/tex}

Explanation